T3B102

Question 1: This is an easy question. As many flowers as possible should make poison to do this.
^??? Why???

Question 2: Remember that expected value is the sum of each outcome times its probability. The expected value of a roll of a die is for instance:
1/6 * 1 + 1/6 * 2 + 1/6 * 3 + 1/6 * 4 + 1/6 * 5 + 1/6 *6 = 3.5

For each possible strategy, you have to calculate the expected number of flowers eaten, as well as the number of flowers killed by a flower to the right. You must find the probability that 1 flower will be eaten, 2 flowers will be eaten, and so on. If only ONE flower makes poison, this is fairly easy, because the probabilities will be the same for each possible outcome (as in the dice example). But if more than one flower make poison, this is much harder. To give you some numbers: if zero flowers make poison, the expected number of flowers eaten is 10 (all of them). If one makes poison, the expected number of flowers eaten is 5.5.
^... yeah no I just... I don't even know. How on EARTH did he get 5.5???

I solved this using Microsoft Excel, but you should be able to solve it without a computer.

...

But then again, I'm really bad at probability, so, you know.